Chemistry

Alkyl Halides

🧪 Chemistry · Alkyl Halides
📅 Updated Jan 2026 ⏱️ 30 min read 🎯 High-yield

Alkyl Halides — SN1, SN2, E1 & E2 Mechanisms

Complete MDCAT Chemistry chapter on alkyl halides: IUPAC nomenclature, C–X bond polarity, reactivity order, SN1/SN2 nucleophilic substitution, E1/E2 elimination, Zaitsev & Hofmann rules, Walden inversion, and preparation methods. Includes 200 solved MCQs with explanations and year-wise past papers.

⚡Quick Answers to Common Searches

Direct, snippet-optimized answers to the top questions students search about alkyl halides.

What are alkyl halides?

Alkyl halides (haloalkanes) have formula R–X, where X = F, Cl, Br, I bonded to an sp³ carbon. They undergo nucleophilic substitution and elimination.

SN1 vs SN2?

SN1: two-step, carbocation intermediate, first-order, favored by 3° substrates, polar protic solvent, racemization. SN2: one-step, backside attack, second-order, favored by 1° substrates, strong nucleophile, polar aprotic solvent, inversion.

E1 vs E2?

E1: two-step, carbocation intermediate, first-order, favored by 3° + heat. E2: one-step, anti-periplanar, second-order, favored by strong base + 2°/3° substrate.

Reactivity order of R-X?

R–I > R–Br > R–Cl > R–F. Reason: C–I weakest bond, I⁻ best leaving group. Despite C–F being most polar, F⁻ is poor leaving group.

What is Zaitsev's rule?

Major product of elimination is the more substituted (more stable) alkene. E.g., 2-bromobutane + alc. KOH → mostly 2-butene (not 1-butene).

What is Hofmann rule?

Bulky bases (e.g., t-butoxide) give the less substituted alkene (Hofmann product) because they cannot reach the more hindered β-hydrogen.

What is Walden inversion?

Inversion of configuration at a chiral carbon during SN2 — the nucleophile attacks from the side opposite to the leaving group.

Aqueous vs alcoholic KOH?

Aqueous KOH → substitution (nucleophile). Alcoholic KOH → elimination (base).

Best leaving group?

I⁻ is the best leaving group (largest, most polarizable, weakest base). Order: I⁻ > Br⁻ > Cl⁻ > F⁻.

Which mechanism for 3° halides?

3° halides favor SN1 (with weak Nu) or E1 (with heat). Strong base shifts them to E2.

What is Finkelstein reaction?

R–Cl + NaI (in dry acetone) → R–I + NaCl↓. Prepares alkyl iodides.

What is Wurtz reaction?

2 R–X + 2 Na (dry ether) → R–R + 2 NaX. Couples two alkyl halides to a longer alkane.

What is Swarts reaction?

R–Cl + AgF (or Hg₂F₂) → R–F + AgCl. Prepares alkyl fluorides.

Polar protic vs aprotic?

Protic (H₂O, ROH) stabilizes carbocations → SN1. Aprotic (DMSO, acetone) leaves nucleophiles un-solvated → SN2.

Why vinyl halides unreactive?

Partial double bond character (resonance), sp² carbon holds electrons tightly, π-cloud blocks backside attack. All three prevent SN1 and SN2.

❓People Also Ask — Alkyl Halides

Questions students most frequently search about this chapter. Answers are direct and exam-focused.

QWhat are alkyl halides?
Alkyl halides (haloalkanes) are organic compounds with general formula R–X where X is F, Cl, Br, or I bonded to an sp³ hybridized carbon. They are versatile synthetic intermediates undergoing nucleophilic substitution (SN1/SN2) and elimination (E1/E2).
QWhat is the difference between SN1 and SN2?
SN1: two-step via carbocation, first-order, tertiary substrates, polar protic solvent, racemization. SN2: one-step backside attack, second-order, methyl/primary substrates, strong nucleophile, polar aprotic solvent, inversion of configuration.
QWhat is the difference between E1 and E2?
E1: two-step via carbocation, first-order, tertiary + heat. E2: one-step anti-periplanar, second-order, strong base + 2°/3° substrate. Both follow Zaitsev's rule unless a bulky base is used (Hofmann product).
QWhy is the C–I bond most reactive?
The C–I bond is the weakest (lowest bond energy), and I⁻ is the best leaving group (largest, most polarizable, weakest conjugate base). Despite C–F being more polar, the strong C–F bond and the poor leaving ability of F⁻ make fluoroalkanes least reactive.
QWhat is Zaitsev's rule?
Zaitsev's rule: in an elimination reaction, the major product is the more substituted (more stable) alkene. For example, 2-bromobutane + alcoholic KOH gives mostly 2-butene (not 1-butene).
QWhat is the Hofmann rule?
The Hofmann rule states that when a bulky base (e.g., tert-butoxide) is used, the major product is the less substituted alkene, because the bulky base cannot reach the more hindered β-hydrogen.
QWhat is Walden inversion?
Walden inversion is the inversion of stereochemical configuration at a chiral carbon during SN2 substitution. The nucleophile attacks from the opposite side of the leaving group, "flipping" the geometry.
QWhich mechanism does tertiary alkyl halide follow?
Tertiary alkyl halides predominantly follow SN1 (with weak nucleophiles) or E1 (with heat) because the tertiary carbocation intermediate is highly stable. With strong bases they shift to E2.
QWhat is the Finkelstein reaction?
Finkelstein reaction prepares alkyl iodides: R–Cl + NaI (in dry acetone) → R–I + NaCl↓. NaCl/NaBr precipitate, driving the reaction forward.
QWhat is the Wurtz reaction?
Wurtz reaction: 2R–X + 2Na (dry ether) → R–R + 2NaX. Couples two alkyl halides into a higher alkane. Works best with primary halides; tertiary halides undergo elimination.
QWhat is the Swarts reaction?
Swarts reaction: R–Cl + AgF (or Hg₂F₂) → R–F + AgCl. Prepares alkyl fluorides.
QWhy does aqueous KOH give substitution but alcoholic KOH gives elimination?
In aqueous KOH, OH⁻ is a good nucleophile, so substitution dominates. In alcoholic KOH, ethoxide is a stronger base and the non-aqueous environment favors elimination.
QWhy are vinyl halides unreactive?
Vinyl halides are unreactive because (1) C–X bond has partial double bond character via resonance, (2) sp² carbon is more electronegative and holds electrons tighter, (3) the π-cloud blocks backside attack.
QWhat is solvolysis?
Solvolysis is a substitution where the solvent itself acts as the nucleophile (e.g., water in hydrolysis, or alcohol in alcoholysis). It typically proceeds via SN1 with tertiary halides in polar protic solvents.
QHow many MCQs from Alkyl Halides in MDCAT?
Alkyl Halides typically contributes 2–3 MCQs. High-yield because reaction mechanisms (SN1, SN2, E1, E2) form the foundation for later organic chemistry chapters.
QWhat is the effect of temperature on substitution vs elimination?
High temperature favors elimination because elimination produces more molecules (higher entropy), so the TΔS term of the free energy equation dominates at high T.
QWhy is neopentyl chloride slow in SN2 despite being primary?
Even though neopentyl is 1°, the bulky tert-butyl group sterically blocks the backside attack required for SN2, making the reaction extremely slow.
QWhat is a Grignard reagent and how is it prepared?
A Grignard reagent (R–MgX) is prepared from an alkyl halide + Mg in dry ether. Water must be avoided because RMgX reacts with water to form alkane (R–H).
QWhat is stereospecific vs stereoselective?
Stereospecific: the mechanism gives a specific stereoisomer from a specific stereoisomer of reactant (SN2 gives inversion). Stereoselective: one stereoisomer is favored over others (SN1 gives racemization with slight inversion excess).
QWhat is the best way to prepare alkyl chlorides from alcohols?
SOCl₂ in pyridine is preferred — by-products (SO₂ and HCl) are gases, so the product is very pure. PCl₅ and PCl₃ also work but leave side products. HCl/ZnCl₂ (Lucas reagent) works best for 3° alcohols.

📋Syllabus & Learning Outcomes

According to PMDC/PMC MDCAT syllabus, Alkyl Halides cover:

📝Full Notes — Alkyl Halides

1. IUPAC Nomenclature of Alkyl Halides

  • General formula: R–X (X = F, Cl, Br, I).
  • Prefix: fluoro-, chloro-, bromo-, iodo- (alphabetical order).
  • Number the longest chain to give the halogen the lowest possible locant.
  • Examples: CH₃CH₂Br → bromoethane; (CH₃)₂CHCl → 2-chloropropane; CH₂=CHCH₂Br → 3-bromoprop-1-ene.
  • Cyclic halides: chlorocyclohexane.

2. Structure and Reactivity of RX

  • C–X bond polarity: Carbon δ+, halogen δ− (electrophilic carbon).
  • Bond strength: C–F > C–Cl > C–Br > C–I (F strongest, weakest leaving group).
  • Leaving group ability: I⁻ > Br⁻ > Cl⁻ > F⁻ (weak bases are good leaving groups).
  • Reactivity toward nucleophilic substitution/elimination: RI > RBr > RCl > RF.
  • Alkyl halides are versatile synthetic intermediates — undergo substitution or elimination.

3. Nucleophilic Substitution — SN1 & SN2

FeatureSN2SN1
KineticsSecond order (rate = k[RX][Nu])First order (rate = k[RX])
StepsOne concerted (no intermediate)Two: carbocation formation then Nu attack
StereochemistryInversion of configuration (Walden inversion)Racemisation (planar carbocation, attack both faces)
Substrate preferenceCH₃X > 1° > 2° > 3°3° > 2° > 1° > CH₃X
NucleophileStrong nucleophile requiredWeak nucleophile sufficient
SolventPolar aprotic (DMSO, acetone)Polar protic (H₂O, ROH)
Key: Tertiary alkyl halides favor SN1; primary alkyl halides favor SN2. Allylic/benzylic substrates can do both (stabilised carbocation).

4. Elimination — E1 & E2

FeatureE2E1
KineticsSecond order (rate = k[RX][Base])First order (rate = k[RX])
StepsOne concertedTwo: carbocation then H⁺ loss
Substrate3° > 2° > 1° (stable alkene)3° > 2° (carbocation stability)
BaseStrong base required (OH⁻, OR⁻)Weak base often sufficient
StereochemistryAnti-periplanar requiredNo special orientation
Zaitsev's rule: Major product is the more substituted alkene. Bulky bases (t-BuO⁻) give Hofmann product (less substituted).
Competition: SN2 competes with E2; SN1 competes with E1. Strong bases + heat favor elimination. Aqueous KOH → substitution; alcoholic KOH → elimination.

High-Yield Points & Common Traps

  • IUPAC: halogen as prefix; alphabetical order; lowest number to halogen.
  • Reactivity: RI > RBr > RCl > RF (C–X bond strength & leaving group ability).
  • SN2: inversion, one step, 1° substrates, strong Nu, aprotic solvent.
  • SN1: racemisation, two steps, 3° substrates, weak Nu, protic solvent.
  • E2: anti-periplanar geometry; strong base; Zaitsev alkene.
  • E1: carbocation intermediate; competes with SN1; Zaitsev rule.
  • Bulky bases (t-BuO⁻) → Hofmann product (less substituted).
  • Heat favours elimination over substitution.
  • Traps: "SN2 occurs with tertiary alkyl halides" → False (SN1). "E2 requires a carbocation" → False (concerted). "Fluorine is a good leaving group" → False. "SN2 has retention of configuration" → False (inversion).

✅Practice MCQs — Test 1

🧪 Basic Concepts

50 MCQs
1The IUPAC name of the compound (CH₃)₃CCl is:
  • A. Tertiary butyl chloride
  • B. 2-chloro-2-methylpropane
  • C. 1-chloro-1,1-dimethylethane
  • D. Trimethylchloromethane
Answer: B. 2-chloro-2-methylpropane
Longest chain is propane with methyl groups on C2 and Cl on C2 → 2-chloro-2-methylpropane.
2Which of the following is the correct name for CH₃CH(Cl)CH₂CH₃?
  • A. 1-chlorobutane
  • B. 2-chlorobutane
  • C. sec-butyl chloride
  • D. 3-chlorobutane
Answer: B. 2-chlorobutane
Four-carbon chain with Cl on C2 → 2-chlorobutane (sec-butyl chloride is the common name).
3What is the IUPAC name for iso-propyl bromide?
  • A. 1-bromopropane
  • B. 2-bromopropane
  • C. 1-bromoisopropane
  • D. 2-bromoisopropane
Answer: B. 2-bromopropane
Isopropyl bromide is CH₃CHBrCH₃ → IUPAC name 2-bromopropane.
4The compound 1-chloro-2,2-dimethylpropane is also known as:
  • A. Neopentyl chloride
  • B. Isobutyl chloride
  • C. Isopentyl chloride
  • D. n-pentyl chloride
Answer: A. Neopentyl chloride
Neopentyl chloride is common name for (CH₃)₃CCH₂Cl.
5A dihalide where two halogen atoms are attached to the same carbon atom is called:
  • A. Vicinal dihalide
  • B. Geminal dihalide
  • C. Isolated dihalide
  • D. Secondary dihalide
Answer: B. Geminal dihalide
Geminal dihalide: both halogens on same carbon; vicinal on adjacent carbons.
6The IUPAC name for CH₂=CH-CH₂Br is:
  • A. 1-bromoprop-2-ene
  • B. 3-bromoprop-1-ene
  • C. Allyl bromide
  • D. 3-bromopropene
Answer: B. 3-bromoprop-1-ene
Three-carbon chain with double bond between C1 and C2, Br on C3 → 3-bromoprop-1-ene.
7Which of the following is a secondary alkyl halide?
  • A. Isobutyl chloride
  • B. Isopropyl chloride
  • C. Neopentyl chloride
  • D. Ethyl chloride
Answer: B. Isopropyl chloride
Isopropyl chloride: (CH₃)₂CHCl, the carbon with Cl is attached to two other carbons (secondary).
8Identify the correct IUPAC name for CH₃C(CH₃)₂CH₂Br:
  • A. 1-bromo-2,2-dimethylpropane
  • B. 2,2-dimethyl-1-bromopropane
  • C. 3-bromo-2,2-dimethylpropane
  • D. Neopentyl bromide
Answer: A. 1-bromo-2,2-dimethylpropane
Longest chain is propane with two methyls on C2 and Br on C1 → 1-bromo-2,2-dimethylpropane.
9The suffix used in the IUPAC system for alkyl halides is:
  • A. -ide
  • B. -ol
  • C. -ane (with halo- prefix)
  • D. -yl
Answer: C. -ane (with halo- prefix)
Alkyl halides are named as haloalkanes, e.g., bromoethane, not using a suffix.
10What is the structure of 2-bromo-3-methylbutane?
  • A. CH₃CH(Br)CH(CH₃)₂
  • B. CH₃C(Br)₂CH₂CH₃
  • C. (CH₃)₂CHCH₂CH₂Br
  • D. CH₃CH₂CH(Br)CH₂CH₃
Answer: A. CH₃CH(Br)CH(CH₃)₂
Four-carbon chain with Br on C2 and methyl on C3 → CH₃CHBrCH(CH₃)₂.
11In alkyl halides, the C-X bond is polar because:
  • A. Carbon is more electronegative than halogens
  • B. Halogen is more electronegative than carbon
  • C. Both have equal electronegativity
  • D. The bond is purely ionic
Answer: B
Halogens (F, Cl, Br, I) are more electronegative than carbon, creating a dipole with carbon δ+.
12Which of the following alkyl halides is the most reactive?
  • A. R-F
  • B. R-Cl
  • C. R-Br
  • D. R-I
Answer: D. R-I
C-I bond is weakest and I⁻ is the best leaving group, making R-I most reactive in substitution.
13The reactivity of alkyl halides is primarily determined by:
  • A. Bond length only
  • B. Bond polarity only
  • C. Both bond polarity and bond energy
  • D. Molecular weight
Answer: C
Both the polarity (attracting nucleophile) and bond strength (ease of breaking) affect reactivity.
14Which C-X bond has the highest bond energy?
  • A. C-F
  • B. C-Cl
  • C. C-Br
  • D. C-I
Answer: A. C-F
C-F bond is strongest due to small size and high electronegativity of F (bond energy ~485 kJ/mol).
15In the C-X bond, the carbon atom acts as:
  • A. A nucleophile
  • B. An electrophile
  • C. A free radical
  • D. A base
Answer: B. An electrophile
Carbon has partial positive charge (δ+) and is attacked by nucleophiles.
16Which of the following is the strongest nucleophile in a polar protic solvent?
  • A. F⁻
  • B. Cl⁻
  • C. Br⁻
  • D. I⁻
Answer: D. I⁻
In polar protic solvents, nucleophilicity increases down the group due to less solvation of larger ions; I⁻ is best.
17The partial positive charge on the carbon of an alkyl halide is due to:
  • A. Inductive effect
  • B. Resonance effect
  • C. Electromeric effect
  • D. Hyperconjugation
Answer: A. Inductive effect
Electron-withdrawing halogen pulls electrons through sigma bonds (inductive effect).
18Which factor makes R-I more reactive than R-F despite R-F being more polar?
  • A. I⁻ is a better leaving group
  • B. C-I bond is weaker
  • C. Size of iodine atom
  • D. All of the above
Answer: D. All of the above
C-I bond is weakest and I⁻ is stable leaving group; size also aids in polarizability.
19Alkyl halides are insoluble in water because:
  • A. They are non-polar
  • B. They cannot form hydrogen bonds with water
  • C. They are heavier than water
  • D. They react with water to form alcohols
Answer: B
Alkyl halides are non-polar and cannot form H-bonds with water, hence insoluble.
20The hybridisation of the carbon atom in an alkyl halide is:
  • A. sp
  • B. sp²
  • C. sp³
  • D. dsp²
Answer: C. sp³
Carbon in alkyl halides is sp³ hybridized (tetrahedral).
21The SN2 mechanism follows _____ kinetics.
  • A. First order
  • B. Second order
  • C. Zero order
  • D. Third order
Answer: B. Second order
Rate = k[RX][Nu⁻], bimolecular → second order.
22In which mechanism does the nucleophile attack from the side opposite to the leaving group?
  • A. SN1
  • B. SN2
  • C. E1
  • D. E2
Answer: B. SN2
SN2 proceeds via backside attack, causing inversion of configuration.
23Which alkyl halide is most likely to undergo SN1 reaction?
  • A. Methyl chloride
  • B. Ethyl chloride
  • C. Isopropyl chloride
  • D. Tertiary butyl chloride
Answer: D. Tertiary butyl chloride
Tertiary carbocation is most stable, so (CH₃)₃CCl undergoes SN1 readily.
24The SN1 reaction is a _____ step process.
  • A. One
  • B. Two
  • C. Three
  • D. Four
Answer: B. Two
Two steps: ionization (slow) then nucleophilic attack (fast).
25The intermediate formed in an SN1 reaction is a:
  • A. Carbanion
  • B. Carbocation
  • C. Free radical
  • D. Transition state only
Answer: B. Carbocation
Ionization produces a carbocation intermediate.
26Complete inversion of configuration (Walden Inversion) is a characteristic of:
  • A. SN1
  • B. SN2
  • C. E2
  • D. Both SN1 and SN2
Answer: B. SN2
SN2 proceeds with backside attack, leading to inversion.
27A racemic mixture is obtained in which type of substitution?
  • A. SN2
  • B. SN1
  • C. E1
  • D. E2
Answer: B. SN1
SN1 proceeds via planar carbocation, attack from either side gives racemic mixture.
28SN2 reactions are favored in which type of solvent?
  • A. Polar protic
  • B. Polar aprotic
  • C. Non-polar
  • D. Purely aqueous
Answer: B. Polar aprotic
Polar aprotic solvents (e.g., DMSO, acetone) solvate cations but not anions, enhancing nucleophilicity.
29The molecularity of an SN1 reaction is:
  • A. 1
  • B. 2
  • C. 3
  • D. 0
Answer: A. 1
Rate-determining step involves only one molecule (alkyl halide), so unimolecular.
30Which of the following is the best leaving group?
  • A. OH⁻
  • B. F⁻
  • C. I⁻
  • D. NH₂⁻
Answer: C. I⁻
I⁻ is a weak base and large, making it the best leaving group.
31The rate of an SN2 reaction depends on the concentration of:
  • A. Substrate only
  • B. Nucleophile only
  • C. Both substrate and nucleophile
  • D. Neither
Answer: C
Rate = k[RX][Nu⁻], depends on both.
32Primary alkyl halides generally follow the _____ mechanism.
  • A. SN1
  • B. SN2
  • C. E1
  • D. E2
Answer: B. SN2
Primary carbocations are unstable, so primary halides undergo SN2.
33The rate-determining step in SN1 is:
  • A. Attack of the nucleophile
  • B. Ionization of the C-X bond
  • C. Deprotonation
  • D. Formation of the product
Answer: B
Slow step is formation of carbocation.
34Stability of carbocations follows the order:
  • A. 1° > 2° > 3°
  • B. 3° > 2° > 1° > Methyl
  • C. Methyl > 1° > 2° > 3°
  • D. 2° > 3° > 1°
Answer: B
Tertiary most stable due to hyperconjugation and inductive effects.
35In SN2 reactions, the transition state involves:
  • A. A three-coordinated carbon
  • B. A five-coordinated carbon
  • C. A planar carbocation
  • D. A carbanion
Answer: B
Transition state has carbon with five groups (pentacoordinate).
36Elimination reactions of alkyl halides result in the formation of:
  • A. Alcohols
  • B. Alkenes
  • C. Alkanes
  • D. Ethers
Answer: B. Alkenes
Dehydrohalogenation produces alkenes.
37The E2 mechanism is a _____ step process.
  • A. One
  • B. Two
  • C. Three
  • D. Multiple
Answer: A. One
Concerted (one-step) process.
38Dehydrohalogenation of alkyl halides is an example of:
  • A. α-elimination
  • B. β-elimination
  • C. γ-elimination
  • D. Substitution
Answer: B. β-elimination
Removal of H and X from adjacent carbons (β-carbons).
39According to Saytzeff's Rule, the major product in elimination is the one with:
  • A. The least substituted double bond
  • B. The most substituted double bond
  • C. The longest carbon chain
  • D. The most terminal double bond
Answer: B
More substituted alkene is more stable (major product).
40E1 reactions follow _____ kinetics.
  • A. First order
  • B. Second order
  • C. Third order
  • D. Zero order
Answer: A. First order
Rate = k[RX], unimolecular.
41Which reagent is typically used for the dehydrohalogenation of alkyl halides?
  • A. Aqueous KOH
  • B. Alcoholic KOH
  • C. Dilute H₂SO₄
  • D. Na in ether
Answer: B. Alcoholic KOH
Alcoholic KOH promotes elimination (E2) over substitution.
42In an E2 reaction, the base abstracts a proton from the:
  • A. α-carbon
  • B. β-carbon
  • C. γ-carbon
  • D. Halogen atom
Answer: B. β-carbon
Proton is removed from carbon adjacent to the one bearing halogen (β-carbon).
43Tertiary alkyl halides favored by a strong base and high temperature will undergo:
  • A. SN1
  • B. SN2
  • C. E2
  • D. Addition
Answer: C. E2
Strong base + high T + 3° halide → E2 elimination.
44Which mechanism involves the formation of a carbocation intermediate?
  • A. E2
  • B. E1
  • C. SN2
  • D. None
Answer: B. E1
E1 proceeds via carbocation intermediate.
45The molecularity of an E2 reaction is:
  • A. 1
  • B. 2
  • C. 0
  • D. 3
Answer: B. 2
Bimolecular: involves both alkyl halide and base.
46High temperature generally favors _____ over _____.
  • A. Substitution, Elimination
  • B. Elimination, Substitution
  • C. SN2, SN1
  • D. E1, E2
Answer: B
Elimination has higher entropy (more molecules), favored at high T.
47A bulky base like potassium tert-butoxide tends to favor:
  • A. Substitution
  • B. Elimination
  • C. Addition
  • D. Rearrangement
Answer: B. Elimination
Bulky bases cannot easily attack backside, so elimination (E2) is favored.
48Aqueous KOH promotes _____ while alcoholic KOH promotes _____.
  • A. Elimination, Substitution
  • B. Substitution, Elimination
  • C. SN1, SN2
  • D. Oxidation, Reduction
Answer: B
Aqueous favors substitution (nucleophile OH⁻), alcoholic favors elimination (base).
49Which of the following favors the SN2 mechanism over E2?
  • A. Tertiary alkyl halide
  • B. Strong, bulky base
  • C. Primary alkyl halide and a small nucleophile
  • D. High temperature
Answer: C
Primary halides have less steric hindrance, favoring SN2; small nucleophile also helps.
50The reaction of ethyl bromide with aqueous NaOH gives:
  • A. Ethene
  • B. Ethanol
  • C. Ethane
  • D. Ethyl ethanoate
Answer: B. Ethanol
Nucleophilic substitution gives ethanol.

✅Practice MCQs — Test 2

🧪 Advanced Concepts

50 MCQs
1How many structural isomers are possible for the molecular formula C₄H₉Br?
  • A. 2
  • B. 3
  • C. 4
  • D. 5
Answer: C. 4
Four isomers: 1-bromobutane, 2-bromobutane, 1-bromo-2-methylpropane, 2-bromo-2-methylpropane.
2The IUPAC name of the compound (CH₃)₂C(Cl)CH(CH₃)₂ is:
  • A. 2-chloro-2,3-dimethylbutane
  • B. 3-chloro-2,3-dimethylbutane
  • C. 2-isopropyl-2-chloropropane
  • D. 2,3-dimethyl-2-chlorobutane
Answer: A
Longest chain is butane with methyls on C2 and C3 and Cl on C2 → 2-chloro-2,3-dimethylbutane.
3Which of the following represents a 'vicinal' dihalide?
  • A. CH₃CH(Cl)₂
  • B. Cl-CH₂-CH₂-Cl
  • C. CH₃CCl₂CH₃
  • D. Cl-CH₂-CH₂-CH₂-Cl
Answer: B. Cl-CH₂-CH₂-Cl
Vicinal dihalides have halogens on adjacent carbons.
4The correct IUPAC name for CH₃CH(Cl)CH=CH₂ is:
  • A. 3-chlorobut-1-ene
  • B. 2-chlorobut-3-ene
  • C. 1-chloro-1-methylprop-2-ene
  • D. 3-chlorobut-3-ene
Answer: A. 3-chlorobut-1-ene
Four-carbon chain with double bond at C1 and Cl at C3 → 3-chlorobut-1-ene.
5Which of the following is a 'Benzylic' halide?
  • A. Chlorobenzene
  • B. C₆H₅CH₂Cl
  • C. C₆H₅CH(Cl)CH₃
  • D. Both B and C
Answer: D
Benzylic halides have halogen on carbon directly attached to benzene ring.
6Neopentyl chloride (2,2-dimethyl-1-chloropropane) is a primary alkyl halide, yet it is extremely slow in SN2 reactions. Why?
  • A. It forms an unstable carbocation
  • B. Severe steric hindrance from the bulky tert-butyl group
  • C. The C-Cl bond is too strong
  • D. It prefers SN1 because of its structure
Answer: B
The neopentyl group has three methyls blocking the backside attack.
7Arrange the following in increasing order of C-X bond strength:
  • A. CH₃I < CH₃Br < CH₃Cl < CH₃F
  • B. CH₃F < CH₃Cl < CH₃Br < CH₃I
  • C. CH₃Cl < CH₃F < CH₃I < CH₃Br
  • D. CH₃Br < CH₃I < CH₃F < CH₃Cl
Answer: A
Bond strength decreases from F to I: C-F strongest, C-I weakest.
8In which of the following solvents would the nucleophilicity of F⁻ be the highest?
  • A. Water (H₂O)
  • B. Ethanol (C₂H₅OH)
  • C. Dimethyl sulfoxide (DMSO)
  • D. Methanol (CH₃OH)
Answer: C. DMSO
Polar aprotic solvents (DMSO) do not solvate anions well, making F⁻ more nucleophilic.
9Which of the following compounds has the highest dipole moment?
  • A. CH₃F
  • B. CH₃Cl
  • C. CH₃Br
  • D. CH₃I
Answer: B. CH₃Cl
CH₃Cl has the highest dipole (1.87 D) due to optimal charge separation and bond length.
10The relative rate of SN2 reaction for R-Cl, R-Br, and R-I follows the order:
  • A. R-Cl > R-Br > R-I
  • B. R-I > R-Br > R-Cl
  • C. R-Br > R-I > R-Cl
  • D. R-I > R-Cl > R-Br
Answer: B
Better leaving group (I⁻) gives faster SN2 rate.
11In an SN1 reaction of an optically active alkyl halide, the product is usually:
  • A. 100% Inverted
  • B. 100% Retained
  • C. Mostly racemized with slight excess of inversion
  • D. Mostly retained with slight excess of inversion
Answer: C
Carbocation intermediate leads to racemization, but solvent shielding may give slight inversion.
12The transition state of an SN2 reaction is best described as:
  • A. sp² hybridized carbon with a pentacoordinate geometry
  • B. sp³ hybridized carbon with a planar geometry
  • C. sp² hybridized carbon with a p-orbital overlapping with two groups
  • D. sp hybridized carbon
Answer: A
Transition state has carbon with five bonds (trigonal bipyramidal).
13Doubling the concentration of the nucleophile in an SN1 reaction will:
  • A. Double the rate
  • B. Quadruple the rate
  • C. Have no effect on the rate
  • D. Halve the rate
Answer: C
SN1 rate depends only on [RX], not on nucleophile concentration.
14Which of the following will react fastest with OH⁻ in an SN2 mechanism?
  • A. CH₃CH₂CH₂Br
  • B. (CH₃)₂CHCH₂Br
  • C. (CH₃)₃CCH₂Br
  • D. CH₃CH₂Br
Answer: D. CH₃CH₂Br
Least steric hindrance among primary halides; ethyl bromide is less hindered than n-propyl.
15The 'Rate = k[RX]' expression belongs to a reaction that involves:
  • A. Simultaneous bond breaking and bond making
  • B. Formation of a carbocation intermediate
  • C. A backside attack by a strong nucleophile
  • D. Walden inversion
Answer: B
First-order kinetics indicates unimolecular step (carbocation formation).
16Which alkyl halide is essentially inert toward BOTH SN1 and SN2 reactions at room temperature?
  • A. Ethyl chloride
  • B. Vinyl chloride
  • C. Isopropyl bromide
  • D. Benzyl chloride
Answer: B. Vinyl chloride
Vinyl halides (C=C-X) have partial double bond character, making C-X bond very strong and unreactive.
17In SN1 reactions, the solvent acts as a nucleophile in a process called:
  • A. Hydrolysis
  • B. Solvolysis
  • C. Pyrolysis
  • D. Electrolysis
Answer: B. Solvolysis
Solvolysis is substitution where solvent is the nucleophile (e.g., water or alcohol).
18Which carbocation is the MOST stable?
  • A. (CH₃)₃C⁺
  • B. C₆H₅CH₂⁺
  • C. CH₂=CH-CH₂⁺
  • D. (C₆H₅)₃C⁺
Answer: D. (C₆H₅)₃C⁺
Triphenylmethyl carbocation is highly stabilized by resonance with three benzene rings.
19If we use a 'Polar Aprotic' solvent like Acetone, which mechanism is accelerated?
  • A. SN1
  • B. SN2
  • C. E1
  • D. All of them
Answer: B. SN2
Polar aprotic solvents enhance nucleophilicity, favoring SN2.
20The energy profile diagram of an SN1 reaction shows:
  • A. One peak (one transition state)
  • B. Two peaks and one valley (intermediate)
  • C. Three peaks
  • D. A continuous downward slope
Answer: B
Two transition states with a carbocation intermediate (valley).
21The E2 mechanism requires the leaving group and the β-hydrogen to be:
  • A. Syn-periplanar
  • B. Anti-periplanar
  • C. Gauche
  • D. Cis to each other
Answer: B. Anti-periplanar
Anti-periplanar arrangement is required for optimal orbital overlap in E2.
22When 2-bromobutane reacts with alcoholic KOH, the major product is 2-butene. This follows:
  • A. Hofmann's rule
  • B. Saytzeff's rule
  • C. Markovnikov's rule
  • D. Anti-Markovnikov's rule
Answer: B. Saytzeff's rule
More substituted alkene (2-butene) is major product (Saytzeff).
23Which of the following bases would most likely favor the 'Hofmann' (least substituted) product in an E2 reaction?
  • A. C₂H₅O⁻ (Ethoxide)
  • B. OH⁻ (Hydroxide)
  • C. (CH₃)₃CO⁻ (tert-butoxide)
  • D. CH₃O⁻ (Methoxide)
Answer: C
Bulky base (tert-butoxide) abstracts less hindered β-hydrogen, giving Hofmann product.
24The dehydrohalogenation of tertiary butyl bromide with alcoholic KOH follows which kinetics?
  • A. First order
  • B. Second order
  • C. Zero order
  • D. Third order
Answer: B. Second order
E2 is bimolecular, second order overall (first order in each reactant).
25In the E1 mechanism, the rate-determining step is:
  • A. Removal of β-hydrogen by base
  • B. Formation of the carbocation
  • C. Formation of the double bond
  • D. Attack of the nucleophile
Answer: B
Ionization to form carbocation is slow step.
26Which of the following is NOT true for E2 reactions?
  • A. It is a concerted reaction
  • B. Rate depends on the concentration of base
  • C. Rearrangements are common
  • D. It is a bimolecular process
Answer: C
E2 is concerted; no carbocation intermediate, so no rearrangements.
27What is the major product when 1-bromo-1-methylcyclohexane undergoes E2 elimination?
  • A. 1-methylcyclohexene
  • B. Methylenecyclohexane
  • C. Cyclohexane
  • D. 1-bromocyclohexene
Answer: A. 1-methylcyclohexene
More substituted alkene (1-methylcyclohexene) is Saytzeff product.
28High temperature favors elimination over substitution because:
  • A. ΔH is more negative
  • B. The entropy factor (TΔS) becomes more dominant
  • C. The activation energy for substitution increases
  • D. Nucleophiles become weaker at high temperatures
Answer: B
Elimination has higher entropy (more molecules), so TΔS term favors it at high T.
29Which alkyl halide cannot undergo a β-elimination reaction?
  • A. CH₃CH₂Cl
  • B. CH₃Cl
  • C. (CH₃)₃CCl
  • D. CH₃CH(Cl)CH₃
Answer: B. CH₃Cl
Methyl chloride has no β-hydrogens, so cannot eliminate.
30The reactivity of alkyl halides towards E2 elimination follows the order:
  • A. 1° > 2° > 3°
  • B. 3° > 2° > 1°
  • C. 2° > 1° > 3°
  • D. All are equally reactive
Answer: B
More substituted halides have more β-hydrogens and form more stable alkenes, so faster E2.
31CH₃CH₂Br + NaCN (in DMSO) produces CH₃CH₂CN. This is an example of:
  • A. SN1
  • B. SN2
  • C. E1
  • D. E2
Answer: B. SN2
NaCN is a strong nucleophile, polar aprotic solvent DMSO favors SN2.
32A 3° alkyl halide reacts with a strong, small base (like CH₃O⁻) at high temperature. The major product is formed via:
  • A. SN2
  • B. E2
  • C. SN1
  • D. E1
Answer: B. E2
Strong base + high T + 3° halide → E2 elimination.
33Secondary alkyl halides can undergo both substitution and elimination. To favor SN2 over E2, one should use:
  • A. A strong, bulky base
  • B. A weak nucleophile
  • C. A good nucleophile that is a weak base (like I⁻ or CN⁻)
  • D. High temperature
Answer: C
Good nucleophile that is a weak base (e.g., I⁻, CN⁻) favors substitution over elimination.
34The reaction of (CH₃)₃CBr with water (H₂O) results in (CH₃)₃COH and some (CH₃)₂C=CH₂. This competitive process is:
  • A. SN2 vs E2
  • B. SN1 vs E1
  • C. SN1 vs E2
  • D. SN2 vs E1
Answer: B. SN1 vs E1
Water is weak nucleophile/base; tertiary halide undergoes SN1 and E1.
35Which of the following is a 'weak nucleophile/weak base'?
  • A. CH₃O⁻
  • B. H₂O
  • C. NH₂⁻
  • D. C₂H₅O⁻
Answer: B. H₂O
Water is a weak nucleophile and weak base.
36Alkyl iodides are often prepared from alkyl chlorides using NaI in acetone. This is called the:
  • A. Wurtz reaction
  • B. Finkelstein reaction
  • C. Swarts reaction
  • D. Frankland reaction
Answer: B. Finkelstein reaction
Finkelstein reaction: R-Cl + NaI → R-I + NaCl (driven by precipitation of NaCl in acetone).
37Which reagent is used to convert an alcohol into an alkyl chloride with the highest purity (as the other products are gases)?
  • A. PCl₃
  • B. PCl₅
  • C. SOCl₂ / pyridine
  • D. HCl / ZnCl₂
Answer: C. SOCl₂ / pyridine
SOCl₂ produces HCl and SO₂ gases, leaving pure alkyl chloride.
38The reaction 2RX + 2Na → R-R + 2NaX is known as:
  • A. Grignard reaction
  • B. Wurtz reaction
  • C. Sabatier-Senderens reaction
  • D. Cannizzaro reaction
Answer: B. Wurtz reaction
Wurtz reaction couples two alkyl halides using sodium metal.
39Which of the following cannot be used to prepare a Grignard reagent?
  • A. CH₃Br
  • B. C₂H₅I
  • C. CH₃CH₂OH
  • D. C₆H₅Br
Answer: C. CH₃CH₂OH
Grignard reagents are prepared from alkyl/aryl halides and Mg in dry ether; alcohols react with Mg.
40The Swarts reaction is specifically used for the synthesis of:
  • A. Alkyl iodides
  • B. Alkyl fluorides
  • C. Alkyl bromides
  • D. Alkanes
Answer: B. Alkyl fluorides
Swarts reaction: R-Cl + AgF or Hg₂F₂ → R-F.
41The C-I bond is the most reactive in nucleophilic substitution because:
  • A. Iodine is the most electronegative
  • B. The bond has the lowest dissociation energy
  • C. I⁻ is the weakest base among halides
  • D. Both B and C
Answer: D
C-I bond weakest and I⁻ is good leaving group (weak base).
42Which factor most significantly decreases the rate of an SN2 reaction?
  • A. Increasing the polarity of the solvent
  • B. Increasing the number of β-substituents
  • C. Using a better leaving group
  • D. Increasing the nucleophile concentration
Answer: B
Steric hindrance from β-substituents slows backside attack.
43The induction of a positive charge on the carbon of CH₃-Cl is partially compensated by:
  • A. Resonance of chlorine
  • B. Hyperconjugation of methyl group
  • C. The electronegativity of carbon
  • D. The d-orbitals of chlorine
Answer: B
Hyperconjugation from C-H bonds stabilizes the partial positive charge.
44In SN1 reactions, which step is the fastest?
  • A. Breaking of the C-X bond
  • B. Attack of the nucleophile on the carbocation
  • C. Proton loss from the nucleophile
  • D. Solvent cage formation
Answer: B
Carbocation is highly reactive, so nucleophilic attack is very fast.
45Which alkyl halide will have the highest boiling point?
  • A. CH₃CH₂CH₂CH₂Cl
  • B. CH₃CH₂CH(Cl)CH₃
  • C. (CH₃)₃CCl
  • D. (CH₃)₂CHCH₂Cl
Answer: A
n-Butyl chloride has the largest surface area, hence the highest boiling point.
46A compound X with formula C₃H₇Cl reacts with aqueous KOH to give Y, and with alcoholic KOH to give Z. If Z can decolorize bromine water, X is:
  • A. 1-chloropropane
  • B. 2-chloropropane
  • C. Either A or B
  • D. 1,2-dichloropropane
Answer: C
Both 1- and 2-chloropropane give propene, which decolorizes Br₂ water.
47SN2 reactions are 'Stereospecific.' This means:
  • A. They always produce a racemic mixture
  • B. The stereochemistry of the product is determined by the stereochemistry of the reactant
  • C. They only occur with chiral molecules
  • D. They are very fast
Answer: B
Stereospecific means a given stereoisomer of reactant gives a specific stereoisomer of product.
48Which of the following is a 'super' leaving group often used in advanced organic synthesis?
  • A. OH⁻
  • B. Cl⁻
  • C. OTs⁻ (Tosylate)
  • D. NH₂⁻
Answer: C. OTs⁻
Tosylate (TsO⁻) is an excellent leaving group due to resonance stabilization.
49What is the effect of doubling the volume of the solvent in an SN2 reaction?
  • A. Rate stays the same
  • B. Rate is halved
  • C. Rate is quartered
  • D. Rate doubles
Answer: C. Rate is quartered
Doubling volume halves concentrations of both reactants, so rate becomes 1/4.
50Identify the correct statement regarding alkyl halides:
  • A. They are more reactive than alkanes
  • B. They have lower boiling points than corresponding alkanes
  • C. They are completely soluble in water
  • D. The C-X bond is non-polar
Answer: A
Alkyl halides are more reactive due to polar C-X bond.

✅Practice MCQs — Test 3

🧪 Exam-Level Questions

50 MCQs
1The IUPAC name for the 'Freon-12' refrigerant (CF₂Cl₂) is:
  • A. Dichlorodifluoromethane
  • B. Difluorodichloromethane
  • C. Carbon difluoride dichloride
  • D. 1,1-dichloro-1,1-difluoromethane
Answer: A. Dichlorodifluoromethane
Freon-12 is dichlorodifluoromethane (CCl₂F₂).
2Which of the following alkyl halides can exist as a pair of enantiomers?
  • A. 2-bromopropane
  • B. 2-bromobutane
  • C. 1-bromobutane
  • D. 2-bromo-2-methylpropane
Answer: B. 2-bromobutane
2-bromobutane has a chiral carbon (C2 attached to Br, H, CH₃, C₂H₅).
3The correct IUPAC name for CH₃C≡C-CH(Cl)CH₃ is:
  • A. 2-chloropent-3-yne
  • B. 4-chloropent-2-yne
  • C. 2-chloro-3-pentyne
  • D. 4-chloro-2-pentyne
Answer: B. 4-chloropent-2-yne
Five-carbon chain with triple bond between C2 and C3, Cl on C4 → 4-chloropent-2-yne.
4Identify the total number of monochlorinated products of neopentane:
  • A. 1
  • B. 2
  • C. 3
  • D. 4
Answer: A. 1
Neopentane (2,2-dimethylpropane) has only one type of hydrogen (all methyls equivalent), so one monochlorinated product.
5The dipole moment of CH₃Cl (1.87 D) is higher than CH₃F (1.85 D) despite Fluorine being more electronegative. This is due to:
  • A. The very short C-F bond length
  • B. Fluorine's high ionization potential
  • C. Chlorine's d-orbital participation
  • D. The sp³ hybridization difference
Answer: A
μ = q × d; although q is larger for C-F, the bond length (d) is shorter, so product is slightly smaller.
6Arrange in decreasing order of boiling point: (I) n-butyl chloride, (II) isobutyl chloride, (III) sec-butyl chloride, (IV) tert-butyl chloride.
  • A. I > II > III > IV
  • B. IV > III > II > I
  • C. I > III > II > IV
  • D. II > I > III > IV
Answer: C
Boiling point depends on surface area and branching. n-butyl (least branched) > sec-butyl > isobutyl > tert-butyl (most branched).
7In which bond is the 'Polarizability' factor most dominant for its reactivity?
  • A. C-F
  • B. C-Cl
  • C. C-Br
  • D. C-I
Answer: D. C-I
Iodine is most polarizable, making C-I bond easily distorted in transition state.
8The C-X bond involves the overlap of an sp³ orbital of carbon with:
  • A. s-orbital of halogen
  • B. p-orbital of halogen
  • C. d-orbital of halogen
  • D. sp³ orbital of halogen
Answer: B
Halogens use their p-orbitals for bonding.
9Which alkyl halide is the most stable toward thermal decomposition?
  • A. CH₃F
  • B. CH₃Cl
  • C. CH₃Br
  • D. CH₃I
Answer: A. CH₃F
C-F bond is strongest, so most thermally stable.
10When 2-bromo-3-methylbutane undergoes SN1 solvolysis in ethanol, the major product is:
  • A. 2-ethoxy-3-methylbutane
  • B. 2-ethoxy-2-methylbutane (via hydride shift)
  • C. 3-ethoxy-2-methylbutane
  • D. 2-methyl-2-butene
Answer: B
Initial carbocation at C2 undergoes hydride shift to form more stable tertiary carbocation, then ethanol attacks.
11The formation of a 'tight ion pair' in SN1 reactions leads to:
  • A. Complete racemization
  • B. Complete inversion
  • C. Partial inversion with partial racemization
  • D. Complete retention
Answer: C
Tight ion pair (still associated) can shield one side, leading to partial inversion.
12Which of the following substrates is MOST reactive toward SN1 due to resonance stabilization?
  • A. Benzyl chloride
  • B. p-Methoxybenzyl chloride
  • C. p-Nitrobenzyl chloride
  • D. Chlorobenzene
Answer: B
p-Methoxybenzyl chloride forms carbocation stabilized by resonance with methoxy (electron-donating).
13In the reaction of neopentyl alcohol with HCl to form neopentyl chloride, the reaction is slow because it must proceed through:
  • A. SN2 with steric hindrance
  • B. SN1 with a primary carbocation (very unstable)
  • C. E2 mechanism
  • D. SN1 with a methyl shift
Answer: A
Neopentyl carbocation would be primary and very unstable; SN2 is blocked by steric hindrance, so reaction is slow.
14Which solvent would maximize the rate of SN1 for tert-butyl chloride?
  • A. 100% Ethanol
  • B. 50% Water / 50% Ethanol
  • C. 100% Acetone
  • D. 100% Benzene
Answer: B
Polar protic solvents stabilize carbocation; water is most polar, but 50% water/ethanol gives high polarity.
15In an SN2 transition state, the incoming nucleophile and the leaving group are at an angle of:
  • A. 90°
  • B. 109.5°
  • C. 120°
  • D. 180°
Answer: D. 180°
Linear arrangement: 180°.
16Which of the following is the 'Nucleophilicity' order in Polar Aprotic solvents (like DMF)?
  • A. I⁻ > Br⁻ > Cl⁻ > F⁻
  • B. F⁻ > Cl⁻ > Br⁻ > I⁻
  • C. Cl⁻ > F⁻ > I⁻ > Br⁻
  • D. They are all equal
Answer: B
In polar aprotic solvents, nucleophilicity follows basicity order: F⁻ most nucleophilic.
17Which of the following will have the HIGHEST rate of SN2 reaction?
  • A. CH₃-CH₂-Br
  • B. CH₃-CH₂-CH₂-Br
  • C. CH₃-O-CH₂-Cl
  • D. C₆H₅-Br
Answer: C
α-haloether (CH₃-O-CH₂-Cl) has enhanced reactivity due to resonance stabilization of transition state.
18Why are 'Bridgehead' halides like 1-chlorobicyclo[2.2.2]octane inert to SN2?
  • A. The back-side is blocked by the cage structure
  • B. The carbon cannot achieve sp² planar geometry
  • C. The C-Cl bond is too strong
  • D. Both A and B
Answer: D
Bridgehead carbons are inaccessible for backside attack and cannot become planar (required for SN1 as well).
19In the E2 elimination of 2-bromobutane, the formation of 'trans-2-butene' as the major product over 'cis-2-butene' is because:
  • A. Trans is more thermodynamically stable
  • B. The transition state leading to trans has less steric repulsion
  • C. It follows Hofmann's rule
  • D. Cis-2-butene cannot be formed
Answer: B
Anti-periplanar elimination favors trans (less steric strain in transition state).
20Which of the following will give the 'Hofmann product' (1-butene) as the major product?
  • A. CH₃CH₂CH(Br)CH₃ + CH₃O⁻
  • B. CH₃CH₂CH(Br)CH₃ + (CH₃)₃CO⁻
  • C. CH₃CH₂CH(F)CH₃ + CH₃O⁻
  • D. Both B and C
Answer: D
Bulky base (tert-butoxide) or poor leaving group (F) favor Hofmann product.
21For an E2 reaction to occur in a cyclohexane ring, the leaving group and the β-hydrogen must be:
  • A. Both Axial
  • B. Both Equatorial
  • C. One Axial, one Equatorial
  • D. Both Cis
Answer: A
Anti-periplanar requirement means both must be axial (for trans-diaxial elimination).
22The dehydrohalogenation of neopentyl bromide with a strong base yields 2-methyl-2-butene. This occurs via:
  • A. E2 mechanism
  • B. E1 mechanism involving a methyl shift
  • C. E1cb mechanism
  • D. SN1 followed by elimination
Answer: B
E1 with carbocation rearrangement (methyl shift) gives more substituted alkene.
23The 'Kinetic Isotope Effect' (k_H / k_D ≈ 7) is observed in which mechanism?
  • A. SN1
  • B. SN2
  • C. E2
  • D. E1
Answer: C. E2
E2 involves breaking C-H bond in rate-determining step, so large primary isotope effect.
24A 2-alkyl halide reacts with KCN in CH₃OH. The product is mostly R-CN. If the same reaction is done with CH₃OK, the product is mostly an alkene. Why?
  • A. CN⁻ is a better nucleophile than a base
  • B. CH₃O⁻ is a stronger base than CN⁻
  • C. CN⁻ is bulkier
  • D. Both A and B
Answer: D
CN⁻ is good nucleophile, weak base → substitution; CH₃O⁻ is strong base → elimination.
25The reaction of 3-bromo-2,2-dimethylbutane with ethanol at 100°C leads primarily to:
  • A. SN1 product
  • B. E1 product (2,3-dimethyl-2-butene)
  • C. SN2 product
  • D. E2 product
Answer: B
Tertiary carbocation after rearrangement gives elimination (E1).
26In the presence of a 'Hard Base' like RO⁻, the reaction is more likely to follow:
  • A. Substitution
  • B. Elimination
  • C. Addition
  • D. Rearrangement
Answer: B
Hard bases are strong bases, favor elimination over substitution.
27Which factor LEAST affects the competition between SN2 and E2?
  • A. Strength of the base
  • B. Temperature
  • C. Steric hindrance of the substrate
  • D. The color of the reactant
Answer: D
Color has no effect on reaction mechanism.
28When isopropyl bromide reacts with sodium ethoxide (C₂H₅ONa), the products are a mixture of ether and alkene. To increase the yield of the ether, one should:
  • A. Increase the temperature
  • B. Decrease the temperature
  • C. Use tert-butoxide instead
  • D. Use a polar aprotic solvent
Answer: B
Lower temperature favors substitution over elimination.
29In the synthesis of R-F using Hg₂F₂, the reaction is known as:
  • A. Finkelstein reaction
  • B. Swarts reaction
  • C. Wurtz reaction
  • D. Corey-House synthesis
Answer: B. Swarts reaction
Swarts reaction uses Hg₂F₂ or AgF to make alkyl fluorides.
30The 'Lucas Reagent' (HCl + anhydrous ZnCl₂) reacts fastest with:
  • A. Primary alcohols
  • B. Secondary alcohols
  • C. Tertiary alcohols
  • D. Phenol
Answer: C. Tertiary alcohols
Tertiary alcohols form carbocations fastest, giving immediate turbidity.
31The order of reactivity of HX with alcohols to form alkyl halides is:
  • A. HI > HBr > HCl
  • B. HCl > HBr > HI
  • C. HBr > HI > HCl
  • D. HI > HCl > HBr
Answer: A
HI is strongest acid and best nucleophile (I⁻), so fastest.
32During the preparation of a Grignard reagent (RMgX), why must the ether be 'absolute' (water-free)?
  • A. Water acts as a catalyst
  • B. Water reacts with RMgX to form an alkane
  • C. Water prevents the dissolution of Magnesium
  • D. Water makes the reaction too fast
Answer: B
RMgX reacts vigorously with water to give RH.
33The reaction 2CH₃Cl + 2Na → C₂H₆ + 2NaCl is an example of:
  • A. Nucleophilic substitution
  • B. Free radical coupling
  • C. Electrophilic addition
  • D. Carbene insertion
Answer: A. Nucleophilic substitution
Wurtz reaction is a nucleophilic substitution (coupling).
34The 'Alpha-Effect' in nucleophilicity is observed in species like HO-O⁻. It makes them:
  • A. Weaker nucleophiles
  • B. Stronger nucleophiles than expected from their basicity
  • C. More prone to elimination
  • D. Insoluble
Answer: B
Alpha-effect: adjacent atom with lone pairs enhances nucleophilicity.
35Vinyl halides are unreactive towards SN2 because:
  • A. The C-X bond has partial double bond character due to resonance
  • B. The carbon is sp² hybridized (more electronegative, holds electrons tighter)
  • C. Back-side attack is blocked by the π-cloud
  • D. All of the above
Answer: D
All factors contribute to low reactivity.
36Which of the following is a 'Soft' nucleophile?
  • A. OH⁻
  • B. RS⁻
  • C. F⁻
  • D. NH₂⁻
Answer: B. RS⁻
RS⁻ (thiolate) is soft (large, polarizable).
37In E1cb mechanism (Elimination Unimolecular Conjugate Base), the intermediate is a:
  • A. Carbocation
  • B. Carbanion
  • C. Free radical
  • D. Benzyne
Answer: B. Carbanion
E1cb involves deprotonation to form carbanion intermediate.
38Chlorination of methane in the presence of UV light is a:
  • A. Nucleophilic substitution
  • B. Electrophilic substitution
  • C. Free radical substitution
  • D. Elimination reaction
Answer: C. Free radical substitution
Free radical halogenation.
39Arrange the stability of the following radicals: (I) Vinyl, (II) Allyl, (III) Benzyl, (IV) Methyl.
  • A. III > II > IV > I
  • B. II > III > IV > I
  • C. I > IV > II > III
  • D. IV > I > II > III
Answer: A
Benzyl > Allyl > Methyl > Vinyl (vinyl least stable).
40The reaction of R-Br with AgNO₂ gives R-NO₂ as the major product, while with KNO₂ it gives R-ONO. This is because:
  • A. AgNO₂ is ionic
  • B. KNO₂ is covalent
  • C. NO₂⁻ is an ambident nucleophile
  • D. Silver is a catalyst
Answer: C
NO₂⁻ can attack via N (nitro) or O (nitrite); Ag⁺ favors N-attack, K⁺ favors O-attack.
41What is the product when CHCl₃ is treated with Ag powder?
  • A. CH₄
  • B. C₂H₂ (Ethyne)
  • C. C₂H₄
  • D. C₂H₆
Answer: B. C₂H₂
2CHCl₃ + 6Ag → C₂H₂ + 6AgCl.
42The chemical name of 'Tear Gas' is:
  • A. Chloropicrin (CCl₃NO₂)
  • B. Chloretone
  • C. Westron
  • D. Mustard gas
Answer: A. Chloropicrin
Chloropicrin (trichloronitromethane) is tear gas.
43Which of the following is used as an antiseptic under the name 'Iodoform'?
  • A. CH₂I₂
  • B. CHI₃
  • C. CI₄
  • D. CH₃I
Answer: B. CHI₃
Iodoform is triiodomethane (CHI₃).
44Allyl chloride is more reactive than n-propyl chloride towards SN1 because:
  • A. Allyl carbocation is resonance stabilized
  • B. Allyl group is electron withdrawing
  • C. It involves sp² carbon
  • D. None
Answer: A
Allyl carbocation is stabilized by resonance.
45The reaction of R-X with Na in the presence of dry ether to give R-R fails when R is:
  • A. Methyl
  • B. Ethyl
  • C. Tertiary butyl (yields mostly alkene via E2)
  • D. Isopropyl
Answer: C
Tertiary halides undergo elimination with Na, giving alkene.
46DDT is prepared by the reaction of Chlorobenzene with:
  • A. Chlorine
  • B. Chloral
  • C. Chloroform
  • D. Carbon tetrachloride
Answer: B. Chloral
DDT: condensation of chlorobenzene with chloral (CCl₃CHO).
47'Walden Inversion' occurs at:
  • A. Chiral carbon
  • B. Any carbon
  • C. Only primary carbon
  • D. Only tertiary carbon
Answer: A
Walden inversion is inversion of configuration at a chiral center.
48Identify the correct statement for SN1 reactions:
  • A. Rate ∝ [Nucleophile]
  • B. 100% inversion occurs
  • C. Favored by high dielectric constant solvents
  • D. Single step reaction
Answer: C
High dielectric constant solvents stabilize carbocation, favoring SN1.
49The compound 'Chloropicrin' is chemically:
  • A. Trichloronitromethane (CCl₃NO₂)
  • B. Trichloromethane
  • C. Tetrachloromethane
  • D. Dichloromethane
Answer: A
Chloropicrin is CCl₃NO₂, used as tear gas and fungicide.
50Which of the following reactions is used to convert an alkyl halide to an alkane?
  • A. Wurtz reaction
  • B. Grignard reagent + H₂O
  • C. Reduction with Zn/HCl
  • D. All of the above
Answer: D
All these methods reduce alkyl halides to alkanes.

📄Past Paper MCQs

📅 Actual MDCAT / NUMS Questions

50 MCQs
1Which of the following alkyl halides is the most reactive towards nucleophilic substitution?
MDCAT 2017, 2021, 2023
  • A. RF
  • B. RCl
  • C. RBr
  • D. RI
Answer: D. RI
C-I bond weakest and I⁻ best leaving group.
2The reaction of ethyl bromide with alcoholic KOH yields:
UHS 2015, 2018, NUMS 2020
  • A. Ethanol
  • B. Ethene
  • C. Ethane
  • D. Ethyl ethanoate
Answer: B. Ethene
Alcoholic KOH promotes elimination to ethene.
3In the SN2 mechanism, the carbon atom of the alkyl halide undergoes:
MDCAT 2016, 2019, 2022
  • A. 100% Inversion of configuration
  • B. 100% Retention of configuration
  • C. Racemization
  • D. 50% Inversion and 50% Retention
Answer: A
Backside attack leads to inversion.
4Which type of alkyl halides follow the SN1 mechanism?
NUMS 2018, 2021, SZABMU 2020
  • A. Primary
  • B. Secondary
  • C. Tertiary
  • D. Methyl halides
Answer: C. Tertiary
Tertiary carbocations most stable.
5The SN1 reaction is a _____ step process and follows _____ kinetics.
MDCAT 2014, 2020
  • A. One, Second order
  • B. Two, First order
  • C. One, First order
  • D. Two, Second order
Answer: B
Two steps; rate depends on [RX] only.
6The stability of carbocations follows the order:
ETEA 2019, UHS 2017
  • A. 1° > 2° > 3°
  • B. 3° > 2° > 1°
  • C. 2° > 3° > 1°
  • D. Methyl > 1° > 2°
Answer: B
Tertiary most stable.
7For the preparation of Grignard Reagent, the solvent used must be:
MDCAT 2015, 2021
  • A. Water-free (Absolute) Ether
  • B. Aqueous Alcohol
  • C. Concentrated H₂SO₄
  • D. Benzene
Answer: A
Grignard reagents react with water.
8Which reagent is best for converting an alcohol to an alkyl chloride because its by-products are gases?
UHS 2016, 2022
  • A. PCl₃
  • B. PCl₅
  • C. SOCl₂ / pyridine
  • D. HCl / ZnCl₂
Answer: C
SOCl₂ gives SO₂ and HCl gases.
9The reaction 2CH₃CH₂Cl + 2Na → C₄H₁₀ + 2NaCl is:
MDCAT 2018, NUMS 2019
  • A. Wurtz reaction
  • B. Frankland reaction
  • C. Hoffman reaction
  • D. Grignard reaction
Answer: A. Wurtz reaction
Wurtz coupling.
10The C-X bond in alkyl halides is polar due to:
NUMS 2022
  • A. Difference in electronegativity between C and X
  • B. Difference in atomic size
  • C. Presence of lone pairs on Carbon
  • D. Hydrogen bonding
Answer: A
Electronegativity difference creates dipole.
11The IUPAC name of neopentyl chloride is:
MDCAT 2021
  • A. 1-chloro-2,2-dimethylpropane
  • B. 2-chloro-2-methylbutane
  • C. 1-chloropentane
  • D. 2,2-dimethyl-3-chloropropane
Answer: A
Neopentyl chloride = (CH₃)₃CCH₂Cl.
12Which of the following is a secondary alkyl halide?
SZABMU 2021
  • A. Isopropyl chloride
  • B. Isobutyl chloride
  • C. Neopentyl chloride
  • D. Ethyl chloride
Answer: A. Isopropyl chloride
Isopropyl chloride: (CH₃)₂CHCl, carbon with Cl attached to two carbons.
13Arrange the C-X bonds in increasing order of bond energy:
ETEA 2020
  • A. C-I < C-Br < C-Cl < C-F
  • B. C-F < C-Cl < C-Br < C-I
  • C. C-Cl < C-F < C-I < C-Br
  • D. C-I < C-Cl < C-Br < C-F
Answer: A
Bond strength: C-F > C-Cl > C-Br > C-I.
14The hybridization of Carbon in CH₃-Cl is:
MDCAT 2019
  • A. sp
  • B. sp²
  • C. sp³
  • D. dsp²
Answer: C. sp³
Tetrahedral sp³.
15Which of the following is an 'ambident' nucleophile?
NUMS 2021
  • A. OH⁻
  • B. CN⁻
  • C. NH₃
  • D. H₂O
Answer: B. CN⁻
CN⁻ can attack through C or N.
16Vinyl chloride is less reactive than ethyl chloride towards SN reactions due to:
DUHS 2018
  • A. Resonance stabilization of the C-Cl bond
  • B. Inductive effect
  • C. Steric hindrance
  • D. Larger size of Vinyl group
Answer: A
Partial double bond character makes C-Cl stronger.
17The correct IUPAC name for CH₃CH(Cl)CH₂CH₂CH₃ is:
MDCAT 2022
  • A. 2-chloropentane
  • B. 4-chloropentane
  • C. sec-pentyl chloride
  • D. 1-methyl-1-chlorobutane
Answer: A. 2-chloropentane
Five-carbon chain with Cl on C2.
18The boiling points of alkyl halides follow the order:
UHS 2014
  • A. RI > RBr > RCl > RF
  • B. RF > RCl > RBr > RI
  • C. RCl > RI > RF > RBr
  • D. RBr > RI > RCl > RF
Answer: A
Higher molecular weight and larger size increase London forces, so RI highest bp.
19Alkyl halides are insoluble in water because:
NUMS 2020
  • A. They are non-polar
  • B. They cannot form hydrogen bonds with water
  • C. They react with water
  • D. They are lighter than water
Answer: B
No H-bonding with water.
20Which alkyl halide will have the highest dipole moment?
ETEA 2021
  • A. CH₃F
  • B. CH₃Cl
  • C. CH₃Br
  • D. CH₃I
Answer: B. CH₃Cl
CH₃Cl has highest dipole (1.87 D).
21In SN2 reactions, the transition state involves a carbon that is:
MDCAT 2023
  • A. Three-coordinated
  • B. Four-coordinated
  • C. Five-coordinated
  • D. Two-coordinated
Answer: C
Pentacoordinate transition state.
22Polar protic solvents (like H₂O or Alcohol) favor which mechanism?
NUMS 2019
  • A. SN2
  • B. SN1
  • C. E2
  • D. Wurtz reaction
Answer: B. SN1
Polar protic solvents stabilize carbocation, favoring SN1.
23The rate of SN2 reaction depends on the concentration of:
UHS 2017
  • A. Alkyl halide only
  • B. Nucleophile only
  • C. Both Alkyl halide and Nucleophile
  • D. Solvent only
Answer: C
Bimolecular: rate = k[RX][Nu⁻].
24Which of the following is the best leaving group?
MDCAT 2020
  • A. F⁻
  • B. Cl⁻
  • C. Br⁻
  • D. I⁻
Answer: D. I⁻
I⁻ is weakest base, best leaving group.
25Dehydrohalogenation of 2-bromobutane with alcoholic KOH gives 2-butene as the major product. This follows:
SZABMU 2022
  • A. Saytzeff's rule
  • B. Markovnikov's rule
  • C. Hofmann's rule
  • D. Anti-Markovnikov's rule
Answer: A
More substituted alkene (Saytzeff).
26E2 elimination is a _____ step process and requires a _____ base.
NUMS 2021
  • A. One, Strong
  • B. Two, Weak
  • C. One, Weak
  • D. Two, Strong
Answer: A
Concerted (one step) with strong base.
27A racemic mixture is the characteristic of which mechanism?
MDCAT 2016
  • A. SN1
  • B. SN2
  • C. E1
  • D. E2
Answer: A. SN1
SN1 via planar carbocation gives racemization.
28High temperature generally favors _____ over _____.
UHS 2019
  • A. Substitution, Elimination
  • B. Elimination, Substitution
  • C. SN2, SN1
  • D. Rearrangement, Elimination
Answer: B
Elimination has higher entropy, favored at high T.
29Which mechanism involves a carbocation intermediate?
MDCAT 2021
  • A. SN1 and E1
  • B. SN2 and E2
  • C. SN1 and SN2
  • D. E1 and E2
Answer: A
Both SN1 and E1 proceed via carbocation.
30Walden Inversion is observed in:
ETEA 2018
  • A. SN1
  • B. SN2
  • C. E1
  • D. E2
Answer: B. SN2
SN2 gives inversion.
31Ethyl bromide reacts with aqueous KOH to form:
MDCAT 2015, 2022
  • A. Ethene
  • B. Ethanol
  • C. Ethane
  • D. Ether
Answer: B. Ethanol
Aqueous KOH gives substitution (ethanol).
32A bulky base like potassium tert-butoxide favors:
NUMS 2022
  • A. SN2
  • B. E2
  • C. SN1
  • D. E1
Answer: B. E2
Bulky base favors E2 elimination.
33The reaction of primary alkyl halides with a strong nucleophile in a polar aprotic solvent follows:
MDCAT 2019
  • A. SN1
  • B. SN2
  • C. E1
  • D. E2
Answer: B. SN2
SN2 favored for primary halides in polar aprotic.
34In SN1 reactions, the first step (formation of carbocation) is:
UHS 2018
  • A. Fast and Exothermic
  • B. Slow and Endothermic
  • C. Fast and Endothermic
  • D. Slow and Exothermic
Answer: B
Ionization is slow and endothermic.
35The reactivity of different halides towards E2 follows the order:
ETEA 2021
  • A. 3° > 2° > 1°
  • B. 1° > 2° > 3°
  • C. 2° > 1° > 3°
  • D. All are equal
Answer: A
More substituted halides give more stable alkenes.
36When CH₃-Cl is treated with Na in the presence of dry ether, the product is:
MDCAT 2020
  • A. CH₄
  • B. C₂H₆
  • C. C₃H₈
  • D. CH₃-O-CH₃
Answer: B. C₂H₆
Wurtz reaction gives ethane.
37Grignard reagent reacts with water to form:
NUMS 2021
  • A. Alcohol
  • B. Alkane
  • C. Aldehyde
  • D. Carboxylic Acid
Answer: B. Alkane
RMgX + H₂O → RH + MgXOH.
38The Swarts reaction is used to prepare:
SZABMU 2020
  • A. Alkyl fluorides
  • B. Alkyl iodides
  • C. Alkyl bromides
  • D. Alkanes
Answer: A
Swarts reaction: R-Cl + AgF → R-F.
39The Finkelstein reaction is specifically used for the synthesis of:
MDCAT 2021
  • A. Alkyl chlorides
  • B. Alkyl iodides
  • C. Alkyl fluorides
  • D. Alcohols
Answer: B. Alkyl iodides
Finkelstein: R-Cl + NaI → R-I + NaCl.
40Which of the following does NOT give a Grignard reagent?
ETEA 2019
  • A. CH₃Br
  • B. C₂H₅OH
  • C. C₆H₅Br
  • D. CH₃I
Answer: B. C₂H₅OH
Alcohols react with Mg but don't form RMgX.
41The order of reactivity of HX with alcohols is:
UHS 2015
  • A. HI > HBr > HCl
  • B. HCl > HBr > HI
  • C. HBr > HI > HCl
  • D. HI > HCl > HBr
Answer: A
HI strongest acid, fastest.
42Carbon tetrachloride (CCl₄) is used as:
NUMS 2018
  • A. Antiseptic
  • B. Fire extinguisher
  • C. Anaesthetic
  • D. Fuel
Answer: B. Fire extinguisher
CCl₄ is non-flammable, used in fire extinguishers (now banned).
43Chloroform (CHCl₃) on oxidation in the presence of light gives:
MDCAT 2014
  • A. Phosgene (COCl₂)
  • B. Formaldehyde
  • C. Formic acid
  • D. Carbon dioxide
Answer: A. Phosgene
CHCl₃ + O₂ → COCl₂ + HCl.
44Which compound is known as 'Iodoform'?
NUMS 2019
  • A. CH₂I₂
  • B. CHI₃
  • C. CH₃I
  • D. CI₄
Answer: B. CHI₃
Iodoform = triiodomethane.
45What happens to the rate of SN2 if the concentration of the alkyl halide is doubled?
MDCAT 2022
  • A. Doubled
  • B. Quadrupled
  • C. Remains same
  • D. Halved
Answer: A. Doubled
Rate ∝ [RX], so doubles.
46What happens to the rate of SN1 if the concentration of the nucleophile is doubled?
MDCAT 2023
  • A. Doubled
  • B. Quadrupled
  • C. Remains same
  • D. Halved
Answer: C. Remains same
SN1 rate independent of [Nu⁻].
47Ethyl chloride reacts with KCN to give:
UHS 2020
  • A. Ethyl cyanide
  • B. Ethyl isocyanide
  • C. Ethyl amine
  • D. Ethane
Answer: A. Ethyl cyanide
KCN gives R-CN (cyanide).
48Ethyl chloride reacts with AgCN to give:
NUMS 2021
  • A. Ethyl cyanide
  • B. Ethyl isocyanide
  • C. Ethyl amine
  • D. Ethane
Answer: B. Ethyl isocyanide
AgCN gives R-NC (isocyanide).
49Chlorination of methane follows which mechanism?
MDCAT 2017
  • A. Nucleophilic substitution
  • B. Electrophilic substitution
  • C. Free radical substitution
  • D. Elimination
Answer: C. Free radical substitution
Free radical mechanism.
50Lucas reagent is a mixture of:
UHS 2016
  • A. HCl + Anhydrous ZnCl₂
  • B. HCl + Hydrated ZnCl₂
  • C. H₂SO₄ + ZnCl₂
  • D. HNO₃ + ZnCl₂
Answer: A
Lucas reagent: conc. HCl + anhydrous ZnCl₂.

🔍Direct Search Queries — Alkyl Halides

Exact search terms students use on Google for this chapter. Click any to jump to the relevant section:

❔Frequently Asked Questions

What are alkyl halides?
Alkyl halides (haloalkanes) are organic compounds with formula R–X where X is F, Cl, Br, or I bonded to an sp³ hybridized carbon. They are versatile synthetic intermediates undergoing nucleophilic substitution (SN1/SN2) and elimination (E1/E2).
What is the difference between SN1 and SN2?
SN1: two-step via carbocation, first-order, tertiary substrates, polar protic solvent, racemization. SN2: one-step backside attack, second-order, methyl/primary substrates, strong nucleophile, polar aprotic solvent, inversion of configuration.
What is the difference between E1 and E2?
E1: two-step via carbocation, first-order, tertiary + heat. E2: one-step anti-periplanar, second-order, strong base + 2°/3° substrate. Both follow Zaitsev's rule unless a bulky base is used (Hofmann product).
Why is the C–I bond most reactive?
The C–I bond is the weakest (lowest bond energy), and I⁻ is the best leaving group (largest, most polarizable, weakest conjugate base). Despite C–F being more polar, the strong C–F bond and the poor leaving ability of F⁻ make fluoroalkanes least reactive.
What is Zaitsev's rule?
Zaitsev's rule: in an elimination reaction, the major product is the more substituted (more stable) alkene. For example, 2-bromobutane + alcoholic KOH gives mostly 2-butene (not 1-butene).
What is the Hofmann rule?
The Hofmann rule states that when a bulky base (e.g., tert-butoxide) is used, the major product is the less substituted alkene, because the bulky base cannot reach the more hindered β-hydrogen.
What is Walden inversion?
Walden inversion is the inversion of stereochemical configuration at a chiral carbon during SN2 substitution. The nucleophile attacks from the opposite side of the leaving group, "flipping" the geometry.
Which mechanism does tertiary alkyl halide follow?
Tertiary alkyl halides predominantly follow SN1 (with weak nucleophiles) or E1 (with heat) because the tertiary carbocation intermediate is highly stable. With strong bases they shift to E2.
What is the Finkelstein reaction?
Finkelstein reaction prepares alkyl iodides: R–Cl + NaI (in dry acetone) → R–I + NaCl↓. NaCl/NaBr precipitate, driving the reaction forward.
What is the Wurtz reaction?
Wurtz reaction: 2R–X + 2Na (dry ether) → R–R + 2NaX. Couples two alkyl halides into a higher alkane. Works best with primary halides; tertiary halides undergo elimination.
What is the Swarts reaction?
Swarts reaction: R–Cl + AgF (or Hg₂F₂) → R–F + AgCl. Prepares alkyl fluorides.
Why does aqueous KOH give substitution but alcoholic KOH gives elimination?
In aqueous KOH, OH⁻ is a good nucleophile, so substitution dominates. In alcoholic KOH, ethoxide is a stronger base and the non-aqueous environment favors elimination.
Why are vinyl halides unreactive?
Vinyl halides are unreactive because (1) C–X bond has partial double bond character via resonance, (2) sp² carbon is more electronegative and holds electrons tighter, (3) the π-cloud blocks backside attack.
What is solvolysis?
Solvolysis is a substitution where the solvent itself acts as the nucleophile (e.g., water in hydrolysis, or alcohol in alcoholysis). It typically proceeds via SN1 with tertiary halides in polar protic solvents.
How many MCQs from Alkyl Halides in MDCAT?
Alkyl Halides typically contributes 2–3 MCQs. High-yield because reaction mechanisms (SN1, SN2, E1, E2) form the foundation for later organic chemistry chapters.
What is the effect of temperature on substitution vs elimination?
High temperature favors elimination because elimination produces more molecules (higher entropy), so the TΔS term dominates at high T.
Why is neopentyl chloride slow in SN2 despite being primary?
Even though neopentyl is 1°, the bulky tert-butyl group sterically blocks the backside attack required for SN2, making the reaction extremely slow.
What is a Grignard reagent and how is it prepared?
A Grignard reagent (R–MgX) is prepared from an alkyl halide + Mg in dry ether. Water must be avoided because RMgX reacts with water to form alkane (R–H).
What is stereospecific vs stereoselective?
Stereospecific: mechanism gives a specific stereoisomer from a specific stereoisomer of reactant (SN2 gives inversion). Stereoselective: one stereoisomer is favored over others (SN1 gives racemization with slight inversion excess).
What is the best way to prepare alkyl chlorides from alcohols?
SOCl₂ in pyridine is preferred — by-products (SO₂ and HCl) are gases, so the product is very pure. PCl₅ and PCl₃ also work but leave side products. HCl/ZnCl₂ (Lucas reagent) works best for 3° alcohols.

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